Whoever finds the pattern i'll give you a cookie

58 -> 377
34 -> 183
27 -> 106
62 -> 461
83 -> ?
someone find the number pls

Canadian education

its 192

JJfriends [#3]

its 192

how

581

i solved it ^_^

581

kirya the femboy solved it but hes banned

Ailed [#6]

581

kirya the femboy solved it but hes banned

bro copied my answer

minte [#5]

581

i solved it ^_^

meatball

446 trust

1552.403

10 and a half in dog years

minte [#5]

581

i solved it ^_^

how did you get that

actually its 676, i used my brain. i know, im a frickin geniuth! 😎

it’s 1

where did you get this problem
a math class
a science class
where

horse69 [#15]

where did you get this problem
a math class
a science class
where

math class

edtheking12 [#16]

math class

what maths
algebra
geometry
calculus
or is it something lower than that

horse69 [#17]

what maths
algebra
geometry
calculus
or is it something lower than that

its just pattern recognition

edtheking12 [#18]

its just pattern recognition

842

Please let me know the answer if you find it

its 367

horse69 [#19]

842

how did you get that

From first glance, the ones is first num’s ones minus 1

brobeans [#23]

From first glance, the ones is first num’s ones minus 1

Hundreds is first num’s tens minus 2 and min 1

bro is trying to get people to do his math homework for him 😭😭😭

Do you have anymore information or context? I think this is impossible to determine what 83 would transform into.

It doesn't follow a linear pattern exactly (nor does it seem to fit other basic curves) which is what I would expect from the whole numbers -> y = 9.4547x - 146.08 with a R^2 of R² = 0.986.

This means 83 would be 638.66 which isn't a whole number either.

I would guess there is some hidden arithmetic equation at play. potentially based on the order of the numbers you gave

edtheking12 [#22]

how did you get that

58 -> 377
34 -> 183
27 -> 106
62 -> 461
83 -> ?
I will refer to the left number as X and right as Y
1) ones digit
X's ones digit is 1 larger than Y's ones digit (8-1 = 7, 4-1 = 3 and on)
so for 83, it will be 2 --> ??2
fairly straightforward
2) tens digit
first X's tens digit(5) + first Y's tens digit(3) = 8, thus 34 --> 183
5+3+2 = 10, 106 and on
so for 83, it will be 5+3+2+6+ 8 = 24, ?42
3) hundreds digit
genearlly, Y's hundreds digit is 2 less than X's.
but we see an exception: 27 --> 106
if we go back to how we got the tens digit, it was 5+3+2, 10. here, we only used the 0 for our solution, and dumped 1. I though that 1 back there should come back here, making it 2-2+1 = 1, 27 --> 106
so for 83, it should be 8-2 = 6, but remember, we dumped the 2 from 24 in tens digit, so 6+2 =8
THEREFORE, ANSWER = 842
Now, there are some faulty reasoning in my solution

1. my solution fails to explain the 7 in tens digit for 58 --> 377. i just said that the first value was given a random number
2. My solution only works if the order matters; for most of these problems, order often doesn't account for the answer, but that was the only way i saw the answer
3. the number becomes invalid if ones digit is 0 , because 0-1 = -1, we can't have that. similar errors could occur with hundreds digit
   BUT, for the given numbers, i didn't come across any error solutions, so i speculate im right? maybe idk

it would be devious to just keyboard slam a bunch of random numbers and say find the pattern

love_trial [#29]

it would be devious to just keyboard slam a bunch of random numbers and say find the pattern

there is a positive correlation so at least some pattern exists

love_trial [#29]

it would be devious to just keyboard slam a bunch of random numbers and say find the pattern

#29

horse69 [#28]

58 -> 377
34 -> 183
27 -> 106
62 -> 461
83 -> ?
I will refer to the left number as X and right as Y
1) ones digit
X's ones digit is 1 larger than Y's ones digit (8-1 = 7, 4-1 = 3 and on)
so for 83, it will be 2 --> ??2
fairly straightforward
2) tens digit
first X's tens digit(5) + first Y's tens digit(3) = 8, thus 34 --> 183
5+3+2 = 10, 106 and on
so for 83, it will be 5+3+2+6+ 8 = 24, ?42
3) hundreds digit
genearlly, Y's hundreds digit is 2 less than X's.
but we see an exception: 27 --> 106
if we go back to how we got the tens digit, it was 5+3+2, 10. here, we only used the 0 for our solution, and dumped 1. I though that 1 back there should come back here, making it 2-2+1 = 1, 27 --> 106
so for 83, it should be 8-2 = 6, but remember, we dumped the 2 from 24 in tens digit, so 6+2 =8
THEREFORE, ANSWER = 842
Now, there are some faulty reasoning in my solution

1. my solution fails to explain the 7 in tens digit for 58 --> 377. i just said that the first value was given a random number
2. My solution only works if the order matters; for most of these problems, order often doesn't account for the answer, but that was the only way i saw the answer
3. the number becomes invalid if ones digit is 0 , because 0-1 = -1, we can't have that. similar errors could occur with hundreds digit
   BUT, for the given numbers, i didn't come across any error solutions, so i speculate im right? maybe idk

This is just a big waste of time if you dont have the 'correct' aswner by whoever elaborated the question

622

firefirefirefire [#32]

This is just a big waste of time if you dont have the 'correct' aswner by whoever elaborated the question

ok

firefirefirefire [#32]

This is just a big waste of time if you dont have the 'correct' aswner by whoever elaborated the question

Some people like puzzles

horse69 [#34]

ok

bruh i appreciated your effort, i was just commenting that this kind of question opens the door for diverse anwsers that only people who made know

brobeans [#30]

there is a positive correlation so at least some pattern exists

anyone can post a bunch of numbers that trend in the same direction doesn't mean there's an intended pattern in there

firefirefirefire [#36]

bruh i appreciated your effort, i was just commenting that this kind of question opens the door for diverse anwsers that only people who made know

i wasnt intending to disagree with you

622