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Pacific Group Omega Tiebreaker

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#1
Yameroooo

whoever won between NS vs Zeta, it will be 3 way tie right ? cause both defeat Talon

3-way tie

  1. Head-to-head Match Series
    • Teams with two matchup head-to-head advantage automatically receives first of the group. Tie-breakers for the remaining two teams are determined using the above head-to-head - - - - - tiebreaker process.
    • If no team has a two matchup head-to-head advantage (all Teams are 1-1 head-to-head), then proceed to next step of the 3-way tie-breaker process.
  2. Map differential
    3.Round differential
    4.Tiebreaker Bo1 match
#2
coltyyy
2
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+

didnt NS lose against talon?

#5
Yameroooo
0
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oh yeah my bad, so if only zeta win then

#3
Killuax54
0
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in simple terms if
Zeta wins they are second seed t1-3rd talon-4th
NS wins they are 4th seed t1-3rd talon-2nd

#12
KaedeTsuneta
0
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+

So if RRQ wins T1 is confirmed 3rd? Damn

#14
Killuax54
0
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+

yep unless rrq loose

#4
DrudaL
0
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+

how about 4 way tie

#7
Hyxagon
0
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i think 4 way ties skip head to head and go straight to map record, which means that if zeta 2-0 ns and ts 2-0 rrq then zeta will be 1st seed

#13
KaedeTsuneta
0
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+

I can't believe this is a possibility...

#6
xDazeline
0
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+

sry brain not braining, but what if rrq lose?

#8
Killuax54
2
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if they loose heavily like13-2 13-3 and ns wins heavily then only they loose the 1st seed

#10
Yameroooo
2
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+

ain't no way rrq lose that, the only reason they are lose against ns cause crazyguy first match, they almost got 2-0 tho

#11
1One1
1
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+

If RRQ lose, 4 way tie is complicated
RRQ #1 80% in 4 way tie because of high map diff and round diff
RRQ could fail if they lose 0-2, Zeta win 2-0, then Zeta win map diff (RRQ +2, Zeta +3)
If RRQ win vs TS, RRQ #1 100% (if course) and only 3 way tie
In 3 way tie, If NS win, NS lose H2H, Talon > T1 > NS
In 3 way tie, If Zeta win, Zeta will have +2 or +3 map diff, Zeta > T1 > Talon

NS can only beat RRQ from round diff
Zeta can only beat RRQ from map diff
Both need RRQ to lose 0-2 and dominated by TS

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