mada = mada
2mada+2mada=4mada
2mada + 2mada = 4mada - 9/2mada + 9/2mada
= √((4mada - 9/2mada)²) + 9/2mada
= √(16mada² - 2∙4mada∙(9/2mada) + (9/2mada)²) + 9/2mada
= √(16mada² - 36mada² + (9/2mada)²) + 9/2mada
= √(-20mada² + (9/2mada)²) + 9/2mada
= √(25mada² - 45mada² + (9/2mada)²) + 9/2mada
= √((5mada - 9/2mada)²) + 9/2mada
= 5mada - 9/2mada + 9/2mada
= 5mada.
So 5mada = 4mada
5mada-4mada =0
mada = 0
Hence mada is zero and doesn't exist .
This whole thing falls apart because of a stupid mistake with the square root and signs. When you get to (4x - (9/2)x)^2, you’re assuming you can just take the square root and keep everything real. But squaring hides any negatives, so if the stuff inside goes negative, you’d end up with imaginary numbers, not real ones.
When you expand (4x - (9/2)x)^2, it actually gives you a negative under the square root — not allowed if you’re sticking to real numbers. So, saying it all magically equals 5x is, simply stupid.
While i do understand this is a joke I have to say, its a bad one
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