3

Because mada = mada

posted in Off Topic
Comments:
Threaded Linear
#1
Whysoseriousss

mada = mada
2mada+2mada=4mada
2mada + 2mada = 4mada - 9/2mada + 9/2mada
= √((4mada - 9/2mada)²) + 9/2mada
= √(16mada² - 2∙4mada∙(9/2mada) + (9/2mada)²) + 9/2mada
= √(16mada² - 36mada² + (9/2mada)²) + 9/2mada
= √(-20mada² + (9/2mada)²) + 9/2mada
= √(25mada² - 45mada² + (9/2mada)²) + 9/2mada
= √((5mada - 9/2mada)²) + 9/2mada
= 5mada - 9/2mada + 9/2mada
= 5mada.

So 5mada = 4mada
5mada-4mada =0
mada = 0

Hence mada is zero and doesn't exist .

#2
n1cf
10
Frags
+

madamatics

#3
cloudberry
6
Frags
+
n1cf [#2]

madamatics

When I make these jokes, I get downvoted and called an NPC :(

#4
jawn
2
Frags
+
cloudberry [#3]

When I make these jokes, I get downvoted and called an NPC :(

i upvote you king don't worry

#5
n1cf
0
Frags
+
cloudberry [#3]

When I make these jokes, I get downvoted and called an NPC :(

you should check discord before i get in between your buttcheeks

#6
Denjisideals
-2
Frags
+

FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎FE!N🔥😎

#7
cloudberry
0
Frags
+
n1cf [#5]

you should check discord before i get in between your buttcheeks

¿Por qué?

#8
K4ziuHa
0
Frags
+

This whole thing falls apart because of a stupid mistake with the square root and signs. When you get to (4x - (9/2)x)^2, you’re assuming you can just take the square root and keep everything real. But squaring hides any negatives, so if the stuff inside goes negative, you’d end up with imaginary numbers, not real ones.
When you expand (4x - (9/2)x)^2, it actually gives you a negative under the square root — not allowed if you’re sticking to real numbers. So, saying it all magically equals 5x is, simply stupid.
While i do understand this is a joke I have to say, its a bad one

#9
Kei8
1
Frags
+
K4ziuHa [#8]

This whole thing falls apart because of a stupid mistake with the square root and signs. When you get to (4x - (9/2)x)^2, you’re assuming you can just take the square root and keep everything real. But squaring hides any negatives, so if the stuff inside goes negative, you’d end up with imaginary numbers, not real ones.
When you expand (4x - (9/2)x)^2, it actually gives you a negative under the square root — not allowed if you’re sticking to real numbers. So, saying it all magically equals 5x is, simply stupid.
While i do understand this is a joke I have to say, its a bad one

nerd

#10
Whysoseriousss
1
Frags
+
K4ziuHa [#8]

This whole thing falls apart because of a stupid mistake with the square root and signs. When you get to (4x - (9/2)x)^2, you’re assuming you can just take the square root and keep everything real. But squaring hides any negatives, so if the stuff inside goes negative, you’d end up with imaginary numbers, not real ones.
When you expand (4x - (9/2)x)^2, it actually gives you a negative under the square root — not allowed if you’re sticking to real numbers. So, saying it all magically equals 5x is, simply stupid.
While i do understand this is a joke I have to say, its a bad one

Nerd

#11
bronzil_enjoyer
1
Frags
+
K4ziuHa [#8]

This whole thing falls apart because of a stupid mistake with the square root and signs. When you get to (4x - (9/2)x)^2, you’re assuming you can just take the square root and keep everything real. But squaring hides any negatives, so if the stuff inside goes negative, you’d end up with imaginary numbers, not real ones.
When you expand (4x - (9/2)x)^2, it actually gives you a negative under the square root — not allowed if you’re sticking to real numbers. So, saying it all magically equals 5x is, simply stupid.
While i do understand this is a joke I have to say, its a bad one

nerd

#12
BabyWizard
0
Frags
+
n1cf [#2]

madamatics

amazing pun king 😍🥰

#13
BabyWizard
0
Frags
+
n1cf [#5]

you should check discord before i get in between your buttcheeks

uhhh i wanna say something very bad

  • Preview
  • Edit
› check that that your post follows the forum rules and guidelines or get formatting help
Sign up or log in to post a comment