Today we saw a match between Team Andbox and Team Sentinels.
In this match we see TenZ and GOD YAYSTER go head to head.
Both of these player are OPs.
In this match we see GOD YAYSTER's team, Andbox, beat TenZ's team, Sentinels 2-0.
We also see GOD YAYSTER drop 52 kills and 175 ADR.
We see TenZ drop 45 kills, and 167 ADR.
This means, mathematically, GOD YAYSTER > TenZ.
This is not all however.
Many people consider either TenZ or WARDELL to the best OPs in Northern America.
To be the best means that you are better than all other OPs, meaning that P* > ALL where ALL is the set {P₀ ... Pₙ} representing all OPers in Northern America.
Looking at both players stats, we can see that TenZ has a slight edge over WARDELL in ACS, KD, KPR and APR, while WARDELL leads in ADR.
At best, we can say that WARDELL is on par with TenZ. At worst we can say he is slightly inferior. i.e Tenz ≥ WARDELL
We can represent the common perspective as:
TenZ > ALL
or
WARDELL = TENZ > ALL
or
TenZ ≥ WARDELL > ALL
Now we introduce the transitive properties of inequality, which state:
"If a ≤ b and b ≤ c, then a ≤ c"
"If a ≤ b and b < c, then a < c."
and
"If a < b and b ≤ c, then a < c."
If we know
WARDELL ≤ TenZ
and
ALL < WARDELL
Then by the transitive property of inequality,
ALL < TenZ
Remember, we know from earlier that TenZ < GOD YAYSTER
So, if we know that ALL < TenZ
and TenZ < GOD YAYSTER
Then we can safely conclude that
ALL < GOD YAYSTER
or, in layman's terms:
GOD YAYSTER > ALL
Q.E.D.
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