If say I wanted to make a vlr account for every single possible pickem for emea lcq, theoretically speaking how many accounts would I have to make?
If say I wanted to make a vlr account for every single possible pickem for emea lcq, theoretically speaking how many accounts would I have to make?
Not relevant and not important
why would you want someone else to waste his time and calculate this for you
permutations/probability were the only things i really disliked in math lol
Edit : its 2^14 different accounts
Pretty simple actually. There 14 games total and 2 outcomes for each one. So 2^14
2^14=16384 accounts idk if this is right
edit: I'm very sure this is right
So if you number the teams from 1 through 8, then for each match, you can either choose the lower number team to win or the higher number team to win, so there are two choices you can make per match. Since there are 14 matches, you would need 2^14=16384 pickems to account for each bracket once.
absolutely bullshit what everyone says
its only in the hundreds of tries not thousands
please guys use common sense its only 8 teams
no way it has 14000 possibility
idk if im thinking of this wrong, but isn't this the correct answer?:
https://math.stackexchange.com/questions/2479349/bracket-of-8-tournament
i know that this is for a single elim bracket, i couldn't find anything for a double elim bracket
and if it's wrong can someone explain why
I understand your confusion. Scroll a bit lower and read the comment by the guy named Kaligule he's explained it somewhat decently.
Basically the op has not considered a fixed starting match up and we're only concerned with the outcomes of the individual matches.
see i thought that at first but then someone corrects him and he proceeds to say "I knew I shouldn't answer sports questions." which made me think he was conceding on being incorrect