They also needed a longer break last year to get franchising up and running. Different reason.
Flag: | New Caledonia |
Registered: | January 31, 2023 |
Last post: | September 5, 2024 at 11:16 AM |
Posts: | 1382 |
They also needed a longer break last year to get franchising up and running. Different reason.
We had to have a longer break to get VCT China up and running, I don't understand complaining. There will be less of a break in future seasons.
the moose is on the loose
i have three PCs, i play solo q on one, duo q on the other, and 5 stack on the last PC all at the same time
pop a caffeinated beverage of your choice and play val, you're not sleeping tonight
PLEASE I WANT TO DO MY PACIFIC PICK EM'S PLEASE I BEG PLEASE
To solve this problem, we can use a combinatorial approach. We'll break it down into cases:
Choose 1 red ball and 1 blue ball from each of the 4 boxes.
Choose 2 red balls and 1 blue ball from one box, and 1 red ball and 2 blue balls from each of the remaining 3 boxes.
Choose 1 red ball and 2 blue balls from one box, and 2 red balls and 1 blue ball from each of the remaining 3 boxes.
Let's calculate the number of ways for each case:
Choosing 1 red ball and 1 blue ball from each of the 4 boxes:
(
3
1
)
×
(
2
1
)
(
1
3
)×(
1
2
) ways from each box
Total ways =
(
3
1
)
×
(
2
1
)
(
1
3
)×(
1
2
)^4
Choosing 2 red balls and 1 blue ball from one box, and 1 red ball and 2 blue balls from each of the remaining 3 boxes:
(
3
2
)
×
(
2
1
)
(
2
3
)×(
1
2
) ways to choose from one box
(
3
1
)
×
(
2
2
)
(
1
3
)×(
2
2
) ways to choose from each of the remaining 3 boxes
Total ways =
(
3
2
)
×
(
2
1
)
×
(
3
1
)
×
(
2
2
)
(
2
3
)×(
1
2
)×(
1
3
)×(
2
2
)^4
Choosing 1 red ball and 2 blue balls from one box, and 2 red balls and 1 blue ball from each of the remaining 3 boxes:
(
3
1
)
×
(
2
2
)
(
1
3
)×(
2
2
) ways to choose from one box
(
3
2
)
×
(
2
1
)
(
2
3
)×(
1
2
) ways to choose from each of the remaining 3 boxes
Total ways =
(
3
1
)
×
(
2
2
)
×
(
3
2
)
×
(
2
1
)
(
1
3
)×(
2
2
)×(
2
3
)×(
1
2
)^4
Now, we sum up the total number of ways from each case to get the final answer. Let's calculate it.
Let's calculate the number of ways for each case:
Choosing 1 red ball and 1 blue ball from each of the 4 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from each box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each box
Total ways =
(
3
1
)
×
(
2
1
)
(
1
3
)×(
1
2
)^4
Choosing 2 red balls and 1 blue ball from one box, and 1 red ball and 2 blue balls from each of the remaining 3 boxes:
(
3
2
)
(
2
3
) ways to choose 2 red balls from one box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from one box
(
3
1
)
(
1
3
) ways to choose 1 red ball from each of the remaining 3 boxes
(
2
2
)
(
2
2
) ways to choose 2 blue balls from each of the remaining 3 boxes
Total ways =
(
3
2
)
×
(
2
1
)
×
(
3
1
)
×
(
2
2
)
(
2
3
)×(
1
2
)×(
1
3
)×(
2
2
)^4
Choosing 1 red ball and 2 blue balls from one box, and 2 red balls and 1 blue ball from each of the remaining 3 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from one box
(
2
2
)
(
2
2
) ways to choose 2 blue balls from one box
(
3
2
)
(
2
3
) ways to choose 2 red balls from each of the remaining 3 boxes
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each of the remaining 3 boxes
Total ways =
(
3
1
)
×
(
2
2
)
×
(
3
2
)
×
(
2
1
)
(
1
3
)×(
2
2
)×(
2
3
)×(
1
2
)^4
Now, let's calculate each of these expressions.
Let's first calculate the number of ways for each case:
Choosing 1 red ball and 1 blue ball from each of the 4 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from each box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each box
Total ways =
(
3
1
)
×
(
2
1
)
(
1
3
)×(
1
2
)^4
Choosing 2 red balls and 1 blue ball from one box, and 1 red ball and 2 blue balls from each of the remaining 3 boxes:
(
3
2
)
(
2
3
) ways to choose 2 red balls from one box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from one box
(
3
1
)
(
1
3
) ways to choose 1 red ball from each of the remaining 3 boxes
(
2
2
)
(
2
2
) ways to choose 2 blue balls from each of the remaining 3 boxes
Total ways =
(
3
2
)
×
(
2
1
)
×
(
3
1
)
×
(
2
2
)
(
2
3
)×(
1
2
)×(
1
3
)×(
2
2
)^4
Choosing 1 red ball and 2 blue balls from one box, and 2 red balls and 1 blue ball from each of the remaining 3 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from one box
(
2
2
)
(
2
2
) ways to choose 2 blue balls from one box
(
3
2
)
(
2
3
) ways to choose 2 red balls from each of the remaining 3 boxes
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each of the remaining 3 boxes
Total ways =
(
3
1
)
×
(
2
2
)
×
(
3
2
)
×
(
2
1
)
(
1
3
)×(
2
2
)×(
2
3
)×(
1
2
)^4
Now, let's calculate each of these expressions.
Let's start by calculating the number of ways for each case:
Choosing 1 red ball and 1 blue ball from each of the 4 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from each box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each box
Total ways =
(
3
1
)
×
(
2
1
)
(
1
3
)×(
1
2
)^4
Choosing 2 red balls and 1 blue ball from one box, and 1 red ball and 2 blue balls from each of the remaining 3 boxes:
(
3
2
)
(
2
3
) ways to choose 2 red balls from one box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from one box
(
3
1
)
(
1
3
) ways to choose 1 red ball from each of the remaining 3 boxes
(
2
2
)
(
2
2
) ways to choose 2 blue balls from each of the remaining 3 boxes
Total ways =
(
3
2
)
×
(
2
1
)
×
(
3
1
)
×
(
2
2
)
(
2
3
)×(
1
2
)×(
1
3
)×(
2
2
)^4
Choosing 1 red ball and 2 blue balls from one box, and 2 red balls and 1 blue ball from each of the remaining 3 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from one box
(
2
2
)
(
2
2
) ways to choose 2 blue balls from one box
(
3
2
)
(
2
3
) ways to choose 2 red balls from each of the remaining 3 boxes
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each of the remaining 3 boxes
Total ways =
(
3
1
)
×
(
2
2
)
×
(
3
2
)
×
(
2
1
)
(
1
3
)×(
2
2
)×(
2
3
)×(
1
2
)^4
Now, let's calculate each of these expressions.
Let's calculate the number of ways for each case:
Choosing 1 red ball and 1 blue ball from each of the 4 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from each box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each box
Total ways =
(
3
1
)
×
(
2
1
)
(
1
3
)×(
1
2
)^4
Choosing 2 red balls and 1 blue ball from one box, and 1 red ball and 2 blue balls from each of the remaining 3 boxes:
(
3
2
)
(
2
3
) ways to choose 2 red balls from one box
(
2
1
)
(
1
2
) ways to choose 1 blue ball from one box
(
3
1
)
(
1
3
) ways to choose 1 red ball from each of the remaining 3 boxes
(
2
2
)
(
2
2
) ways to choose 2 blue balls from each of the remaining 3 boxes
Total ways =
(
3
2
)
×
(
2
1
)
×
(
3
1
)
×
(
2
2
)
(
2
3
)×(
1
2
)×(
1
3
)×(
2
2
)^4
Choosing 1 red ball and 2 blue balls from one box, and 2 red balls and 1 blue ball from each of the remaining 3 boxes:
(
3
1
)
(
1
3
) ways to choose 1 red ball from one box
(
2
2
)
(
2
2
) ways to choose 2 blue balls from one box
(
3
2
)
(
2
3
) ways to choose 2 red balls from each of the remaining 3 boxes
(
2
1
)
(
1
2
) ways to choose 1 blue ball from each of the remaining 3 boxes
The time complexity of searching an element in a red-black (RB) tree is O(log n), where n is the number of nodes in the tree.
I also wanted to say that I have wanted to become more positive on this website because of you.
Thank you for your positivity on this website, Geospliced.
I am sorry that my fellow vlr users are downvoting you.
offseason tourneys mean nothing
They have lost to FNC, a good team
They have lost to LEV, a good team
The only upset in the offseason is the LXT INV and losing to FUR
I feel like c9 is a top 3-5 contender
Mark my words, they will at least do decent this year
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
CHIPI 💥💯🔊 CHIPI👍🥰🤪😋 CHAPA 💗💖🤪😋🔊 CHAPA 💯🥰👌💙 DUBI 🦄✨🧨💗😍 DUBI 😍😍😍🔊💯✨💖💖 DABA 👍💋🔊🤯🎉 DABA 🧨💗💖💖💙 MAGICÒ MÍ 🙋♂️💖💖💗🧨 DUBI 💙💙🎉🎉🦄 DUBI BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM 🧨💥🧨 BOOM🧨💥🧨
If you read the article you would know who B3ar is
Has bbl ever been to champs?
I don’t remember that
I think the ideal map pool is
Imagine nsp 13:0 ts
your name is bigskrossifan with a GE flair, i don't think you should be talking
b0tsio
but in all seriousness, this team looks like top five material
all of these pros have more money than you will ever have
jinggg owns you buddy
Wym I wasn't talking to myself. I was talking to froggy_lol.
I am being nice to Simp4S0m, I'm simply reminding them that they need to take their meds