You Did but this was not confirmed until today.
Flag: | India |
Registered: | February 27, 2024 |
Last post: | August 20, 2024 at 2:30 AM |
Posts: | 1554 |
You Did but this was not confirmed until today.
when you win your games you tend to go through less elim games
GenG lost to TS who didnt even MAKE CHAMPS
We will see, based on the performance of fpx and sen. Bookmark this.
GenG
FPX
TH
SEN
Also will the groups be revealed at Americas grand finals tomorrow?
Nothing stays hidden from me. Nothing.
"I dont know it, but doesnt hurt to believe in it anyways"
is 26% hs not good? can you give me crosshair code
The problem is they have higher dpi mouse, i have a 200 rs around 2-3 dollar mouse
i play in mumbai server so its not that, its just that my knives are always microdots away. Thanks for the tips tho. I ll keep that in mind.
Alright man ill do that too, i do tend to taking close fights with em
my sens is 0.41 on 800 dpi, my table is small and thus i cant play with low sens
I dont think someone can naturally be good at hitting knives
I do and i do hit there, but in matches they just miss so slightly man in matches
Im FLEX player and my fav agents are Chamber, Jett, Omen and cypher
My hs% on avg is 25% , but i always tend to miss my jett knives, like ALWAYS how can i fix that? I dont hit a thing when im updrafting
Its okay i already have the solution now, thanks for trying <3
Nope i was just giving you the question as you seemed confused about the answer key
this is the whole ques
if a curve passes through the point (1,-2) and has slope of the tangent at any point (x,y) on it as (x²-2y)÷x, then the curve also passes through the point: (1) (3,0) (2) (√3,0) (3) (-1,2) (4) (-√2,1)
Now slope means differentiation and if we integrate the slope we get the curve and to find a constant we make use of the point given. But how do i integrate this
Actually the question says (1,-2) does satisfy from that we find the constant, and then we have to find another point that satisfies, from the given options
No thanks a lot nexus, i appereciate it a lot <3 Btw do you know you have the most disliked post on the internet?
Your solution is wrong
I was actually just solving a previous year questions of this chapter, teacher didnt give us the question.
this is the whole ques
if a curve passes through the point (1,-2) and has slope of the tangent at any point (x,y) on it as (x²-2y)÷x, then the curve also passes through the point: (1) (3,0) (2) (√3,0) (3) (-1,2) (4) (-√2,1)
Now slope means differentiation and if we integrate the slope we get the curve and to find a constant we make use of the point given. But how do i integrate this
this is the whole ques
if a curve passes through the point (1,-2) and has slope of the tangent at any point (x,y) on it as (x²-2y)÷x, then the curve also passes through the point: (1) (3,0) (2) (√3,0) (3) (-1,2) (4) (-√2,1)
Now slope means differentiation and if we integrate the slope we get the curve and to find a constant we make use of the point given. But how do i integrate this
yes this is the whole ques
if a curve passes through the point (1,-2) and has slope of the tangent at any point (x,y) on it as (x²-2y)÷x, then the curve also passes through the point: (1) (3,0) (2) (√3,0) (3) (-1,2) (4) (-√2,1)
Now slope means differentiation and if we integrate the slope we get the curve and to find a constant we make use of the point given. But how do i integrate this
i have no idea what any of this means, can you please explain? We havent been taught integration yet so idk what an integrating factor is, i only know basic integration rules that are used in physics for taking elements
yes we havent been taught it yet, we are on AOD rn can you give the full solution
I need help with the integration of this dy/dx = x - 2y/x
i tried to take help from ai but this is what ir proved 💀
The correct answer is (3) (-1,2).
Given the slope of the tangent at any point (x, y) on the curve as (x²-2y)÷x, we can write the differential equation:
dy/dx = (x²-2y)/x
We are also given that the curve passes through the point (1, -2). We can use this information to find the equation of the curve.
Separating the variables, we get:
∫dy = ∫(x²-2y)/x dx
Integrating both sides, we get:
y = (1/3)x³ - 2x + C
Using the point (1, -2), we can find the value of C:
-2 = (1/3)(1)³ - 2(1) + C
C = -4/3
So, the equation of the curve is:
y = (1/3)x³ - 2x - 4/3
Now, we can check if the curve passes through the point (-1, 2):
2 = (1/3)(-1)³ - 2(-1) - 4/3
2 = -1/3 + 2 - 4/3
2 = 2/3 (which is true)
Therefore, the curve also passes through the point (-1, 2).
Well if they are already dead, they will be kept in jail because they might spread a zmb apocalypse !!
Murder for the smart who pretend to be stupid, there is no need to pretend stupid in a debate unless they are trolling
But to destroy the sins, Kru would need Sha(h)zam uk
As an indian i really dont know why we are third